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- Use strings.Builder instead of concatenation - Move smart tree to a separate file - Add missing docstrings
99 lines
3.0 KiB
Go
99 lines
3.0 KiB
Go
package print
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import (
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"git-get/pkg/repo"
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"path/filepath"
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"strings"
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)
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// SmartPrinter implements Printer interface and provides methods for printing repos and their statuses.
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// It's "smart" because it automatically folds branches which only have a single child and indents branches with many children.
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type SmartPrinter struct {
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// length is the size (number of chars) of the currently processed line.
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// It's used to correctly indent the lines with branches status.
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length int
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}
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// Print generates a list of repositories and their statuses.
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func (p *SmartPrinter) Print(root string, repos []*repo.Repo) string {
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tree := buildTree(root, repos)
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return p.printSmartTree(tree)
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}
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// printSmartTree recursively traverses the tree and prints its nodes.
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// If a node contains multiple children, they are be printed in new lines and indented.
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// If a node contains only a single child, it is printed in the same line using path separator.
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// For better readability the first level (repos hosts) is not indented.
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//
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// Example:
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// Following paths:
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// /repos/github.com/user/repo1
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// /repos/github.com/user/repo2
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// /repos/github.com/another/repo
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//
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// will render a tree:
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// /repos/
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// github.com/
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// user/
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// repo1
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// repo2
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// another/repo
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//
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func (p *SmartPrinter) printSmartTree(node *Node) string {
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if node.children == nil {
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// If node is a leaf, print repo name and its status and finish processing this node.
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value := node.val
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// TODO: Ugly
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// If this is called from tests the repo will be nil and we should return just the name without the status.
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if node.repo.Repository == nil {
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return value
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}
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value += " " + printWorktreeStatus(node.repo)
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// Print the status of each branch on a new line, indented to match the position of the current branch name.
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indent := "\n" + strings.Repeat(" ", p.length+len(node.val))
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for _, branch := range node.repo.Status.Branches {
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// Don't print the status of the current branch. It was already printed above.
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if branch.Name == node.repo.Status.CurrentBranch {
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continue
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}
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value += indent + printBranchStatus(branch)
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}
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return value
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}
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val := node.val + string(filepath.Separator)
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shift := ""
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if node.parent == nil {
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// If node is a root, print its children on a new line without indentation.
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shift = "\n"
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} else if len(node.children) == 1 {
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// If node has only a single child, print it on the same line as its parent.
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// Setting node's depth to the same as parent's ensures that its children will be indented only once even if
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// node's path has multiple levels above.
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node.depth = node.parent.depth
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p.length += len(val)
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} else {
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// If node has multiple children, print each of them on a new line
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// and indent them once relative to the parent
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node.depth = node.parent.depth + 1
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shift = "\n" + strings.Repeat(" ", node.depth)
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p.length = 0
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}
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for _, child := range node.children {
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p.length += len(shift)
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val += shift + p.printSmartTree(child)
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p.length = 0
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}
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return val
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}
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