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https://github.com/grdl/git-get.git
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Improve the implementation of the smart tree printer
It now correctly indents lines with branches status
This commit is contained in:
45
pkg/tree.go
45
pkg/tree.go
@@ -86,7 +86,9 @@ func BuildTree(root string, repos []*Repo) *Node {
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return tree
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}
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// RenderTree returns a string representation of repos tree.
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// RenderSmartTree returns a string representation of repos tree.
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// It's "smart" because it automatically folds branches which only have a single child and indents branches with many children.
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//
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// It recursively traverses the tree and prints its nodes.
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// If a node contains multiple children, they are be printed in new lines and indented.
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// If a node contains only a single child, it is printed in the same line using path separator.
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@@ -106,12 +108,35 @@ func BuildTree(root string, repos []*Repo) *Node {
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// repo2
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// another/repo
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//
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func RenderTree(node *Node) string {
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func RenderSmartTree(node *Node) string {
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if node.children == nil {
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// If node is a leaf, print repo name and its status and finish processing this node.
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return node.val + " " + renderWorktreeStatus(node.repo)
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value := node.val
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// TODO: Ugly
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// If this is called from tests the repo will be nil and we should return just the name without the status.
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if node.repo.repo == nil {
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return value
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}
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value += " " + renderWorktreeStatus(node.repo)
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// Print the status of each branch on a new line, indented to match the position of the current branch name.
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indent := "\n" + strings.Repeat(" ", length+len(node.val))
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for _, branch := range node.repo.Status.Branches {
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// Don't print the status of the current branch. It was already printed above.
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if branch.Name == node.repo.Status.CurrentBranch {
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continue
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}
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value += indent + renderBranchStatus(branch)
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}
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return value
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}
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val := node.val + string(filepath.Separator)
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shift := ""
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if node.parent == nil {
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// If node is a root, print its children on a new line without indentation.
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@@ -121,17 +146,25 @@ func RenderTree(node *Node) string {
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// Setting node's depth to the same as parent's ensures that its children will be indented only once even if
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// node's path has multiple levels above.
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node.depth = node.parent.depth
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length += len(val)
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} else {
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// If node has multiple children, print each of them on a new line
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// and indent them once relative to the parent
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node.depth = node.parent.depth + 1
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shift = "\n" + strings.Repeat("\t", node.depth)
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shift = "\n" + strings.Repeat(" ", node.depth)
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length = 0
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}
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val := node.val + string(filepath.Separator)
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for _, child := range node.children {
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val += shift + RenderTree(child)
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length += len(shift)
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val += shift + RenderSmartTree(child)
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length = 0
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}
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return val
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}
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// lenght is the size (number of chars) of the currently processed line.
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// It's used to correctly indent the lines with branches status.
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var length int
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